What is (\partial)/(\partial z)(2x+z^2) ?

The answer to (\partial)/(\partial z)(2x+z^2) is 2z

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(\partial)/(\partial z)(2x+z^2)

\frac{\partial}{\partial z} (2 x + z^{2})

2 z

Solution steps

\frac{\partial}{\partial z} (2 x + z^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (2 x) + \frac{\partial}{\partial z} (z^{2})

\frac{\partial}{\partial z} (2 x) = 0

\frac{\partial}{\partial z} (z^{2}) = 2 z

= 0 + 2 z

Simplify

= 2 z

x \to 0 lim ((x + h)^{2} - 1)

\int ln (2 x - 1) d x

\frac{d}{d x} (2 x^{3} - 3 x)

\frac{d}{d x} (arcsin (\frac{y}{x ^{2} + y ^{2}}))

\int \frac{3 x - 4}{x ^{2} - 2 x} d x

What is (\partial)/(\partial z)(2x+z^2) ?
The answer to (\partial)/(\partial z)(2x+z^2) is 2z