What is the derivative of 2x^3-3x ?

The derivative of 2x^3-3x is 6x^2-3

What is the first derivative of 2x^3-3x ?

The first derivative of 2x^3-3x is 6x^2-3

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\frac{d}{d x} (2 x^{3} - 3 x)

6 x^{2} - 3

Solution steps

\frac{d}{d x} (2 x^{3} - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (3 x)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3 x) = 3

= 6 x^{2} - 3

\frac{d}{d x} (arcsin (\frac{y}{x ^{2} + y ^{2}}))

\int \frac{3 x - 4}{x ^{2} - 2 x} d x

\int 3 x^{2} d x

\int 4 x^{3} - 3 x^{2} + 5 d x

\int (3 x^{2} y^{- 2} + 2 x y^{- 1}) d x

What is the derivative of 2x^3-3x ?
The derivative of 2x^3-3x is 6x^2-3
What is the first derivative of 2x^3-3x ?
The first derivative of 2x^3-3x is 6x^2-3