What is the integral of sqrt(3)x^2 ?

The integral of sqrt(3)x^2 is (x^3)/(sqrt(3))+C

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integral of sqrt(3)x^2

\int 3 x^{2} d x

\frac{x ^{3}}{3} + C

Solution steps

\int 3 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int x^{2} d x

Apply the Power Rule

: \frac{x ^{3}}{3}

= 3 \frac{x ^{3}}{3}

Simplify

3 \frac{x ^{3}}{3} : \frac{x ^{3}}{3}

= \frac{x ^{3}}{3}

Add a constant to the solution

= \frac{x ^{3}}{3} + C

\int 4 x^{3} - 3 x^{2} + 5 d x

\int (3 x^{2} y^{- 2} + 2 x y^{- 1}) d x

\frac{d}{d x} (\frac{( x + 1 ) ( 3 x - 7 )}{3 x + 1})

\int_{- 2}^{2} (x^{2} - 2)^{2} d x

\frac{d}{d x} (1 - (1 - 0.01 x)^{3})

What is the integral of sqrt(3)x^2 ?
The integral of sqrt(3)x^2 is (x^3)/(sqrt(3))+C