What is the derivative of f(x)=1-1/x ?

The derivative of f(x)=1-1/x is 1/(x^2)

What is the first derivative of f(x)=1-1/x ?

The first derivative of f(x)=1-1/x is 1/(x^2)

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derivative of

f (x) = 1 - \frac{1}{x}

\frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (1 - \frac{1}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (\frac{1}{x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{1}{x}) = - \frac{1}{x ^{2}}

= 0 - (- \frac{1}{x ^{2}})

Simplify

= \frac{1}{x ^{2}}

y^{2} = x + 10, y^{2} = 8 - x

\frac{\partial}{\partial x} (\frac{1}{( x + y ) ^{2}})

x \to 1 lim (\frac{1}{1 + x ^{2}})

- 4 x^{2} + 9, x + 7, 0

x^{9}

What is the derivative of f(x)=1-1/x ?
The derivative of f(x)=1-1/x is 1/(x^2)
What is the first derivative of f(x)=1-1/x ?
The first derivative of f(x)=1-1/x is 1/(x^2)