What is (\partial)/(\partial x)(8/(x^2)) ?

The answer to (\partial)/(\partial x)(8/(x^2)) is -(16)/(x^3)

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(\partial)/(\partial x)(8/(x^2))

\frac{\partial}{\partial x} (\frac{8}{x ^{2}})

- \frac{16}{x ^{3}}

Solution steps

\frac{\partial}{\partial x} (\frac{8}{x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{\partial}{\partial x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 8 \frac{\partial}{\partial x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 8 (- 2 x^{- 2 - 1})

Simplify

8 (- 2 x^{- 2 - 1}) : - \frac{16}{x ^{3}}

= - \frac{16}{x ^{3}}

\int \frac{1}{1 - 6 x} d x

f (x) = 3 x^{2} + x + 5

f (x) = - 5 x^{2} + 2 x - 6

x \to 0 + lim (\frac{∣ x - 0 ∣}{0 - x})

\int_{2}^{\infty} x e^{- 4 x} d x

What is (\partial)/(\partial x)(8/(x^2)) ?
The answer to (\partial)/(\partial x)(8/(x^2)) is -(16)/(x^3)