What is the derivative of f(x)=x^2-3x+2 ?

The derivative of f(x)=x^2-3x+2 is 2x-3

What is the first derivative of f(x)=x^2-3x+2 ?

The first derivative of f(x)=x^2-3x+2 is 2x-3

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derivative of

f (x) = x^{2} - 3 x + 2

2 x - 3

Solution steps

\frac{d}{d x} (x^{2} - 3 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 2 x - 3 + 0

Simplify

= 2 x - 3

\frac{s + 1}{( s - 1 ) \cdot ( s - 2 )}

tan (θ) sec (θ)

\int \frac{\frac{d y}{1}}{y} d x

f (x) = \frac{x}{x - 1}, at x = 2

\frac{d}{d x} ((x + 1)^{5})

What is the derivative of f(x)=x^2-3x+2 ?
The derivative of f(x)=x^2-3x+2 is 2x-3
What is the first derivative of f(x)=x^2-3x+2 ?
The first derivative of f(x)=x^2-3x+2 is 2x-3