What is the tangent of f(x)= x/(x-1),\at x=2 ?

The tangent of f(x)= x/(x-1),\at x=2 is y=-x+4

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tangent of f(x)= x/(x-1),\at x=2

tangent of

f (x) = \frac{x}{x - 1}, at x = 2

y = - x + 4

Solution steps

Find the tangent point:

(2, 2)

Find the slope of

f (x) = \frac{x}{x - 1} : \frac{df ( x )}{d x} = - \frac{1}{( x - 1 ) ^{2}}

Compute the slope of

f (x) = \frac{x}{x - 1}

x = 2 : m = - 1

Find the line with slope m=

- 1

and passing through

(2, 2) : y = - x + 4

y = - x + 4

\frac{d}{d x} ((x + 1)^{5})

\frac{d}{d x} (\frac{2}{5} x^{10})

t^{3} sin (t)

f (x) = 4 t^{- \frac{1}{8}}

\int \frac{1}{12 y - 10 y ^{2}} d y

What is the tangent of f(x)= x/(x-1),\at x=2 ?
The tangent of f(x)= x/(x-1),\at x=2 is y=-x+4