What is the integral from 1/2 to 2 of 1/(x^2) ?

The integral from 1/2 to 2 of 1/(x^2) is 3/2

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integral from 1/2 to 2 of 1/(x^2)

\int_{\frac{1}{2}}^{2} \frac{1}{x ^{2}} d x

\frac{3}{2}

Decimal Notation

1.5

Solution steps

\int_{\frac{1}{2}}^{2} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{\frac{1}{2}}^{2}

= [- \frac{1}{x}]_{\frac{1}{2}}^{2}

Compute the boundaries:

\frac{3}{2}

= \frac{3}{2}

e^{x}, e^{4 x}, [0, 1]

x^{3} + 2 x

\int \frac{2}{e ^{4 x}} d x

\frac{d}{d x} (\frac{2 x}{1 - cot ( x )})

\int - sin^{3} (x) cos^{2} (x) d x

What is the integral from 1/2 to 2 of 1/(x^2) ?
The integral from 1/2 to 2 of 1/(x^2) is 3/2