What is (\partial)/(\partial x)((6-x^2y^2)^2) ?

The answer to (\partial)/(\partial x)((6-x^2y^2)^2) is -4xy^2(6-x^2y^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)((6-x^2y^2)^2)

\frac{\partial}{\partial x} ((6 - x^{2} y^{2})^{2})

- 4 x y^{2} (6 - x^{2} y^{2})

Solution steps

\frac{\partial}{\partial x} ((6 - x^{2} y^{2})^{2})

Treat

y

as a constant

Apply the chain rule:

2 (6 - x^{2} y^{2}) \frac{\partial}{\partial x} (6 - x^{2} y^{2})

= 2 (6 - x^{2} y^{2}) \frac{\partial}{\partial x} (6 - x^{2} y^{2})

\frac{\partial}{\partial x} (6 - x^{2} y^{2}) = - 2 y^{2} x

= 2 (6 - x^{2} y^{2}) (- 2 y^{2} x)

Simplify

= - 4 x y^{2} (6 - x^{2} y^{2})

x \to 4 + lim (\frac{4 + x}{4 - x})

h \to 0 lim (6 x + 1 + 3 h)

{\frac{1}{s ^{2} + s - 20}}

\frac{d}{d x} (arcsin (1 - 2 x^{2}))

\frac{d}{d x} (e^{x} + x^{2})

What is (\partial)/(\partial x)((6-x^2y^2)^2) ?
The answer to (\partial)/(\partial x)((6-x^2y^2)^2) is -4xy^2(6-x^2y^2)