What is the derivative of e^x+x^2 ?

The derivative of e^x+x^2 is e^x+2x

What is the first derivative of e^x+x^2 ?

The first derivative of e^x+x^2 is e^x+2x

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\frac{d}{d x} (e^{x} + x^{2})

e^{x} + 2 x

Solution steps

\frac{d}{d x} (e^{x} + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (x^{2}) = 2 x

= e^{x} + 2 x

\frac{d}{d y} (y cos (x))

\frac{\partial}{\partial x} (45 - x^{2} - y^{2})

\frac{d}{d x} (sin (2 x - 2 π))

\int \frac{1}{x ^{2} + 2 x + 5} d x

\frac{\partial}{\partial x} (ln (x^{6} + 1) + y^{2})

What is the derivative of e^x+x^2 ?
The derivative of e^x+x^2 is e^x+2x
What is the first derivative of e^x+x^2 ?
The first derivative of e^x+x^2 is e^x+2x