What is the limit as x approaches 0 of (sin(x)-1)/x ?

The limit as x approaches 0 of (sin(x)-1)/x is diverges

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limit as x approaches 0 of (sin(x)-1)/x

x \to 0 lim (\frac{sin ( x ) - 1}{x})

diverges

Solution steps

x \to 0 lim (\frac{sin ( x ) - 1}{x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{sin ( x ) - 1}{x}) = - \infty

x \to 0 - lim (\frac{sin ( x ) - 1}{x}) = \infty

= diverges

x \to 0 lim (\frac{1}{x} - \frac{1}{x ^{2}} - x)

y^{^{''}} - (\frac{6}{x}) y^{^{'}} - (\frac{3}{x ^{2}}) y = 0

n = 1 \sum \infty n - 1

\frac{d}{d x} ((sin (x))^{6})

\frac{d}{d x} (\frac{x ^{2}}{y})

What is the limit as x approaches 0 of (sin(x)-1)/x ?
The limit as x approaches 0 of (sin(x)-1)/x is diverges