What is the integral from 0 to pi of tan(x) ?

The integral from 0 to pi of tan(x) is diverges

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integral from 0 to pi of tan(x)

\int_{0}^{π} tan (x) d x

diverges

Solution steps

\int_{0}^{π} tan (x) d x

Take the denominator(s) of

tan (x)

and compare to zero:

x = \frac{π}{2}

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{0}^{\frac{π}{2}} tan (x) d x + \int_{\frac{π}{2}}^{π} tan (x) d x

\int_{0}^{\frac{π}{2}} tan (x) d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

n = 1 \sum \infty \frac{1}{5 n}

\int \frac{tan ( x ) - 1}{sec ^{2} ( x )} d x

cos (x) y^{^{'}} + y sin (x) = 1

\int cos^{4} (5 x + 8) d x

n = 1 \sum \infty \frac{n}{3 ^{n}}

What is the integral from 0 to pi of tan(x) ?
The integral from 0 to pi of tan(x) is diverges