What is the sum from n=1 to infinity of n/(3^n) ?

The sum from n=1 to infinity of n/(3^n) is converges

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sum from n=1 to infinity of n/(3^n)

n = 1 \sum \infty \frac{n}{3 ^{n}}

converges

Solution steps

n = 1 \sum \infty \frac{n}{3 ^{n}}

Apply Series Ratio Test:

converges

= converges

\frac{\partial}{\partial θ} (ln (θ + 1))

\int \frac{( e ^{t a n (x)} )}{cos ^{2} ( x )} d x

y^{^{''}} + 5 y^{^{'}} + 2 y = 7

y = 2 x^{3}, (2, 16)

\int \frac{1}{x x + 1} d x

What is the sum from n=1 to infinity of n/(3^n) ?
The sum from n=1 to infinity of n/(3^n) is converges