What is the solution for y^{''}+5y^'+2y=7 ?

The solution for y^{''}+5y^'+2y=7 is y=c_{1}e^{((-5+sqrt(17))t)/2}+c_{2}e^{((-5-sqrt(17))t)/2}+7/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+5y^'+2y=7

y^{^{''}} + 5 y^{^{'}} + 2 y = 7

y = c_{1} e^{\frac{( - 5 + 17 ) t}{2}} + c_{2} e^{\frac{( - 5 - 17 ) t}{2}} + \frac{7}{2}

Solution steps

y^{''} (t) + 5 y^{'} (t) + 2 y = 7

Solve linear ODE:

y = c_{1} e^{\frac{( - 5 + 17 ) t}{2}} + c_{2} e^{\frac{( - 5 - 17 ) t}{2}} + \frac{7}{2}

y = c_{1} e^{\frac{( - 5 + 17 ) t}{2}} + c_{2} e^{\frac{( - 5 - 17 ) t}{2}} + \frac{7}{2}

y = 2 x^{3}, (2, 16)

\int \frac{1}{x x + 1} d x

y = (\frac{x}{1 + x})^{5}

\frac{d}{d x} (2 x \cdot e^{x^{2}})

x \to 25 lim (x - 5)

What is the solution for y^{''}+5y^'+2y=7 ?
The solution for y^{''}+5y^'+2y=7 is y=c_{1}e^{((-5+sqrt(17))t)/2}+c_{2}e^{((-5-sqrt(17))t)/2}+7/2