What is the tangent of f(x)=cos(2x),\at x= pi/6 ?

The tangent of f(x)=cos(2x),\at x= pi/6 is y=-sqrt(3)x+1/2+pi/(2sqrt(3))

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tangent of f(x)=cos(2x),\at x= pi/6

tangent of

f (x) = cos (2 x), at x = \frac{π}{6}

y = - 3 x + \frac{1}{2} + \frac{π}{2 3}

Solution steps

Find the tangent point:

(\frac{π}{6}, \frac{1}{2})

Find the slope of

f (x) = cos (2 x) : \frac{df ( x )}{d x} = - sin (2 x) \cdot 2

Compute the slope of

f (x) = cos (2 x)

x = \frac{π}{6} : m = - 3

Find the line with slope m=

- 3

and passing through

(\frac{π}{6}, \frac{1}{2}) : y = - 3 x + \frac{1}{2} + \frac{π}{2 3}

y = - 3 x + \frac{1}{2} + \frac{π}{2 3}

\frac{d}{d t} (t^{2} - 2)

\frac{\partial}{\partial z} (4 x - yz + 3 y z^{2} + z^{2})

f (x) = sin (x), - \frac{2 π}{3}, \frac{π}{3}

\int \frac{6 x}{( x ^{2} + 3 ) ^{2}} d x

3 - x^{2}, 11 - 6 x

What is the tangent of f(x)=cos(2x),\at x= pi/6 ?
The tangent of f(x)=cos(2x),\at x= pi/6 is y=-sqrt(3)x+1/2+pi/(2sqrt(3))