What is the derivative of f(x)=(x-3)/2 ?

The derivative of f(x)=(x-3)/2 is 1/2

What is the first derivative of f(x)=(x-3)/2 ?

The first derivative of f(x)=(x-3)/2 is 1/2

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derivative of

f (x) = \frac{x - 3}{2}

\frac{1}{2}

Solution steps

\frac{d}{d x} (\frac{x - 3}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{d x}{d x} - \frac{d}{d x} (3))

\frac{d x}{d x} = 1

\frac{d}{d x} (3) = 0

= \frac{1}{2} (1 - 0)

Simplify

= \frac{1}{2}

3 e^{- 4 t} - 5 e^{4 t}

\frac{\partial}{\partial y} (\frac{x}{y ^{2} + x ^{2}})

\int tan^{2} (x + c) + 1 d x

x^{2}, 1

y^{^{''''}} + y^{^{''}} = 0

What is the derivative of f(x)=(x-3)/2 ?
The derivative of f(x)=(x-3)/2 is 1/2
What is the first derivative of f(x)=(x-3)/2 ?
The first derivative of f(x)=(x-3)/2 is 1/2