What is the solution for y^{''''}+y^{''}=0 ?

The solution for y^{''''}+y^{''}=0 is y=c_{1}+c_{2}t+c_{3}cos(t)+c_{4}sin(t)

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y^{''''}+y^{''}=0

y^{^{''''}} + y^{^{''}} = 0

y = c_{1} + c_{2} t + c_{3} cos (t) + c_{4} sin (t)

Solution steps

y^{(4)} (t) + y^{''} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} t + c_{3} cos (t) + c_{4} sin (t)

y = c_{1} + c_{2} t + c_{3} cos (t) + c_{4} sin (t)

\frac{\partial}{\partial x} (x z - e^{x} sin (y))

x \to - 2 lim (\frac{5 x ^{2} + 6}{x})

(\frac{1}{( 1 - x ) ^{2}})^{^{'}}

y = \frac{1}{4 x ^{2}}, y = x, y = \frac{x}{10}

\frac{d}{d x} (\frac{x - 1}{x ^{2} + 4})

What is the solution for y^{''''}+y^{''}=0 ?
The solution for y^{''''}+y^{''}=0 is y=c_{1}+c_{2}t+c_{3}cos(t)+c_{4}sin(t)