What is the derivative of sin(x+csc(x)) ?

The derivative of sin(x+csc(x)) is cos(x)-cot(x)csc(x)

What is the first derivative of sin(x+csc(x)) ?

The first derivative of sin(x+csc(x)) is cos(x)-cot(x)csc(x)

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\frac{d}{d x} (sin (x) + csc (x))

cos (x) - cot (x) csc (x)

Solution steps

\frac{d}{d x} (sin (x) + csc (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (x)) + \frac{d}{d x} (csc (x))

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (csc (x)) = - cot (x) csc (x)

= cos (x) - cot (x) csc (x)

\frac{x d y}{d x} = 2 x e^{x} - y + 6 x^{2}

y^{^{''}} + 2 y^{^{'}} + y = x^{2}

\frac{1}{3} x^{3} - \frac{1}{2} x^{2} - 30 x + 2

y = \frac{2 x + 3}{3 x - 2}

\int 9 cos (x) + 5 d x

What is the derivative of sin(x+csc(x)) ?
The derivative of sin(x+csc(x)) is cos(x)-cot(x)csc(x)
What is the first derivative of sin(x+csc(x)) ?
The first derivative of sin(x+csc(x)) is cos(x)-cot(x)csc(x)