What is the integral of 9cos(x)+5 ?

The integral of 9cos(x)+5 is 9sin(x)+5x+C

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integral of 9cos(x)+5

\int 9 cos (x) + 5 d x

9 sin (x) + 5 x + C

Solution steps

\int 9 cos (x) + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 cos (x) d x + \int 5 d x

\int 9 cos (x) d x = 9 sin (x)

\int 5 d x = 5 x

= 9 sin (x) + 5 x

Add a constant to the solution

= 9 sin (x) + 5 x + C

\frac{\partial}{\partial x} (x^{0.1} y^{0.9})

x \to 0 lim (\frac{sin ( 4 x ^{2} )}{x})

\frac{\partial}{\partial x} (x \cdot y^{2} \cdot z^{3})

(4 x - 3)^{5} (3 - x^{3})^{2}

y^{^{''}} - 16 y^{^{'}} + 64 y = t^{- 2} e^{8 t}