What is laplacetransform sin(3x)+cos(2x) ?

The answer to laplacetransform sin(3x)+cos(2x) is 3/(s^2+9)+s/(s^2+4)

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laplacetransform sin(3x)+cos(2x)

laplace transform

sin (3 x) + cos (2 x)

\frac{3}{s ^{2} + 9} + \frac{s}{s ^{2} + 4}

Solution steps

L {sin (3 x) + cos (2 x)}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {sin (3 x)} + L {cos (2 x)}

L {sin (3 x)} : \frac{3}{s ^{2} + 9}

L {cos (2 x)} : \frac{s}{s ^{2} + 4}

= \frac{3}{s ^{2} + 9} + \frac{s}{s ^{2} + 4}

cos^{2} (x) y^{^{'}} = e^{- y} sin (x)

(2 x^{2} + 7)^{5}

\frac{\partial}{\partial x} (2 e^{x y} ln (x^{2} + y^{2}))

\frac{d}{d x} (\frac{2 - 3 x}{4})

\frac{d}{d v} (x^{v})

What is laplacetransform sin(3x)+cos(2x) ?
The answer to laplacetransform sin(3x)+cos(2x) is 3/(s^2+9)+s/(s^2+4)