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Popular >

x^2y^'+xy=4,y(1)=3

Solution

x^{2} y^{^{'}} + x y = 4, y (1) = 3

Solution

y = \frac{4 ln ( x )}{x} + \frac{3}{x}

Solution steps

x^{2} y^{'} (x) + x y = 4

Solve linear ODE:

y = \frac{4 ln ( x )}{x} + \frac{3}{x}

y = \frac{4 ln ( x )}{x} + \frac{3}{x}

Popular Examples

f (x) = 2 x^{\frac{1}{3}}

integral of (x^4)/((1+x^2)^{3/2)}

\int \frac{x ^{4}}{( 1 + x ^{2} ) ^{\frac{3}{2}}} d x

derivative of x^3+y^3 derivative of

x^{3} + y^{3}

integral of 6e^4

\int 6 e^{4} d x

integral from 1 to 2 of 9sqrt(4x^2-3)

\int_{1}^{2} 9 4 x^{2} - 3 d x

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'+xy=4,y(1)=3 ?
The solution for x^2y^'+xy=4,y(1)=3 is y=(4ln(x))/x+3/x