What is the derivative of x^3+y^3 ?

The derivative of x^3+y^3 is 3x^2

What is the first derivative of x^3+y^3 ?

The first derivative of x^3+y^3 is 3x^2

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derivative of

x^{3} + y^{3}

3 x^{2}

Solution steps

\frac{d}{d x} (x^{3} + y^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (y^{3})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (y^{3}) = 0

= 3 x^{2} + 0

Simplify

= 3 x^{2}

\int 6 e^{4} d x

\int_{1}^{2} 9 4 x^{2} - 3 d x

\frac{\partial}{\partial y} (9 y^{7} x^{8} - 8 y^{6} x^{7})

\int_{0}^{2} π (4 x^{2})^{2} d x

f (- 5) = x^{3} - 2

What is the derivative of x^3+y^3 ?
The derivative of x^3+y^3 is 3x^2
What is the first derivative of x^3+y^3 ?
The first derivative of x^3+y^3 is 3x^2