What is (\partial)/(\partial y)(9y^7x^8-8y^6x^7) ?

The answer to (\partial)/(\partial y)(9y^7x^8-8y^6x^7) is 63x^8y^6-48x^7y^5

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(\partial)/(\partial y)(9y^7x^8-8y^6x^7)

\frac{\partial}{\partial y} (9 y^{7} x^{8} - 8 y^{6} x^{7})

63 x^{8} y^{6} - 48 x^{7} y^{5}

Solution steps

\frac{\partial}{\partial y} (9 y^{7} x^{8} - 8 y^{6} x^{7})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (9 y^{7} x^{8}) - \frac{\partial}{\partial y} (8 y^{6} x^{7})

\frac{\partial}{\partial y} (9 y^{7} x^{8}) = 63 x^{8} y^{6}

\frac{\partial}{\partial y} (8 y^{6} x^{7}) = 48 x^{7} y^{5}

= 63 x^{8} y^{6} - 48 x^{7} y^{5}

\int_{0}^{2} π (4 x^{2})^{2} d x

f (- 5) = x^{3} - 2

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\frac{d}{d x} (n x)

\int \frac{( x + 1 ) ( x - 1 )}{x} d x

What is (\partial)/(\partial y)(9y^7x^8-8y^6x^7) ?
The answer to (\partial)/(\partial y)(9y^7x^8-8y^6x^7) is 63x^8y^6-48x^7y^5