What is the derivative of f(x)=2x^2-3 ?

The derivative of f(x)=2x^2-3 is 4x

What is the first derivative of f(x)=2x^2-3 ?

The first derivative of f(x)=2x^2-3 is 4x

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derivative of

f (x) = 2 x^{2} - 3

4 x

Solution steps

\frac{d}{d x} (2 x^{2} - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3) = 0

= 4 x - 0

Simplify

= 4 x

x - sin (x)

\frac{\partial}{\partial x} (sin (\frac{2 y}{x}))

\frac{d}{d x} (\frac{6}{( 1 + x ) ^{4}})

\frac{d}{d x} (\frac{6 x ^{3} - 2}{x ^{2} - 4})

f (x) = x^{2} + x

What is the derivative of f(x)=2x^2-3 ?
The derivative of f(x)=2x^2-3 is 4x
What is the first derivative of f(x)=2x^2-3 ?
The first derivative of f(x)=2x^2-3 is 4x