What is the tangent of f(x)=x^2+x ?

The tangent of f(x)=x^2+x is y=(2a_{0}+1)x-a_{0}^2

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tangent of f(x)=x^2+x

tangent of

f (x) = x^{2} + x

y = (2 a_{0} + 1) x - a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, a_{0}^{2} + a_{0})

Find the slope of

f (x) = x^{2} + x : \frac{df ( x )}{d x} = 2 x + 1

Compute the slope of

f (x) = x^{2} + x

x = a_{0} : m = 2 a_{0} + 1

Find the line with slope m=

2 a_{0} + 1

and passing through

(a_{0}, a_{0}^{2} + a_{0}) : y = (2 a_{0} + 1) x - a_{0}^{2}

y = (2 a_{0} + 1) x - a_{0}^{2}

\int sec (5 x) tan (5 x) d x

\frac{d}{d x} (sec (\frac{1}{x}))

\int \frac{1}{( x ^{2} + 9 ) ^{\frac{5}{2}}} d x

x \to 1 lim (- 1)

\int \frac{32 r ^{7} d r}{2 - r ^{8}} d x

What is the tangent of f(x)=x^2+x ?
The tangent of f(x)=x^2+x is y=(2a_{0}+1)x-a_{0}^2