What is the d/(dt)(-2asin(2t)+2bcos(2t)) ?

The d/(dt)(-2asin(2t)+2bcos(2t)) is -4acos(2t)-4bsin(2t)

What is the first d/(dt)(-2asin(2t)+2bcos(2t)) ?

The first d/(dt)(-2asin(2t)+2bcos(2t)) is -4acos(2t)-4bsin(2t)

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\frac{d}{d t} (- 2 a sin (2 t) + 2 b cos (2 t))

- 4 a cos (2 t) - 4 b sin (2 t)

Solution steps

\frac{d}{d t} (- 2 a sin (2 t) + 2 b cos (2 t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (2 a sin (2 t)) + \frac{d}{d t} (2 b cos (2 t))

\frac{d}{d t} (2 a sin (2 t)) = 4 a cos (2 t)

\frac{d}{d t} (2 b cos (2 t)) = - 4 b sin (2 t)

= - 4 a cos (2 t) - 4 b sin (2 t)

n = 0 \sum \infty 3 n

x - 1 - 0.5 sin (x)

\int_{8}^{- 1} x^{2} - 8 d x

y^{^{'}} - \frac{6 y}{x} = \frac{y ^{4}}{x ^{12}}

2 x y y^{^{'}} = x^{2} + y^{2}

What is the d/(dt)(-2asin(2t)+2bcos(2t)) ?
The d/(dt)(-2asin(2t)+2bcos(2t)) is -4acos(2t)-4bsin(2t)
What is the first d/(dt)(-2asin(2t)+2bcos(2t)) ?
The first d/(dt)(-2asin(2t)+2bcos(2t)) is -4acos(2t)-4bsin(2t)