What is the solution for y^'-(6y)/x =(y^4)/(x^{12)} ?

The solution for y^'-(6y)/x =(y^4)/(x^{12)} is y=(\sqrt[3]{7}x^6)/(\sqrt[3]{-3x^7+c_{1)}}

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y^'-(6y)/x =(y^4)/(x^{12)}

y^{^{'}} - \frac{6 y}{x} = \frac{y ^{4}}{x ^{12}}

Solution steps

y^{'} (x) - \frac{6 y}{x} = \frac{y ^{4}}{x ^{12}}

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What is the solution for y^'-(6y)/x =(y^4)/(x^{12)} ?
The solution for y^'-(6y)/x =(y^4)/(x^{12)} is y=(\sqrt[3]{7}x^6)/(\sqrt[3]{-3x^7+c_{1)}}