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Popular >

y^{''}+2y^'=-8

Solution

y^{^{''}} + 2 y^{^{'}} = - 8

Solution

y = c_{1} + c_{2} e^{- 2 t} - 4 t

Solution steps

y^{''} (t) + 2 y^{'} (t) = - 8

Solve linear ODE:

y = c_{1} + c_{2} e^{- 2 t} - 4 t

y = c_{1} + c_{2} e^{- 2 t} - 4 t

Popular Examples

(x+1)y^'=-2y+(x+1)^{5/2},y(0)= 11/9

(x + 1) y^{^{'}} = - 2 y + (x + 1)^{\frac{5}{2}}, y (0) = \frac{11}{9}

derivative of 0.41sqrt(x)

\frac{d}{d x} (0.41 x)

(\partial)/(\partial x)(1)

\frac{\partial}{\partial x} (1)

integral of x^3e^{x^2}

\int x^{3} e^{x^{2}} d x

integral of-xsin(x)cos(x)

\int - x sin (x) cos (x) d x

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+2y^'=-8 ?
The solution for y^{''}+2y^'=-8 is y=c_{1}+c_{2}e^{-2t}-4t