What is the integral from-infinity to 0 of 1/(2-4x) ?

The integral from-infinity to 0 of 1/(2-4x) is diverges

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integral from-infinity to 0 of 1/(2-4x)

\int_{- \infty}^{0} \frac{1}{2 - 4 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{2 - 4 x} d x

Compute the indefinite integral:

\int \frac{1}{2 - 4 x} d x = - \frac{1}{4} ln ∣ 2 - 4 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{2 - 4 x} d x =

diverges

= diverges

\int_{a}^{b} f (x) d x

(ln (\frac{x}{4}))^{^{'}}

\int 2 x (2 - x) d x

3^{2^{x^{2}}}

x \to 0 lim (\frac{sin ( x ^{7} )}{x})

What is the integral from-infinity to 0 of 1/(2-4x) ?
The integral from-infinity to 0 of 1/(2-4x) is diverges