What is the derivative of (x^3-x/x) ?

The derivative of (x^3-x/x) is 2x

What is the first derivative of (x^3-x/x) ?

The first derivative of (x^3-x/x) is 2x

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\frac{d}{d x} (\frac{x ^{3} - x}{x})

2 x

Solution steps

\frac{d}{d x} (\frac{x ^{3} - x}{x})

Simplify

\frac{x ^{3} - x}{x} : x^{2} - 1

= \frac{d}{d x} (x^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= 2 x - 0

Simplify

= 2 x

\frac{d}{d x} (\frac{4}{( x ^{3} + 9 ) ^{5}})

\frac{d x}{d t} + 2 t^{5} x^{7} + \frac{x}{t} = 0

n = 0 \sum \infty e^{- 6 n}

(7, - 4), (8, 8)

\frac{d}{d x} (\frac{- ln ( 1 + 6 x )}{x})

What is the derivative of (x^3-x/x) ?
The derivative of (x^3-x/x) is 2x
What is the first derivative of (x^3-x/x) ?
The first derivative of (x^3-x/x) is 2x