What is the sum from n=0 to infinity of e^{-6n} ?

The sum from n=0 to infinity of e^{-6n} is converges

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sum from n=0 to infinity of e^{-6n}

n = 0 \sum \infty e^{- 6 n}

converges

Solution steps

n = 0 \sum \infty e^{- 6 n}

Apply Series Integral Test:

converges

= converges

(7, - 4), (8, 8)

\frac{d}{d x} (\frac{- ln ( 1 + 6 x )}{x})

\int 1 - 2 y d y

\frac{d}{d x} (arctan (g (x)) (x))

\frac{\partial}{\partial x} (3 sin (\frac{6 x}{y}))

What is the sum from n=0 to infinity of e^{-6n} ?
The sum from n=0 to infinity of e^{-6n} is converges