What is (\partial}{\partial x}(3sin(\frac{6x)/y)) ?

The answer to (\partial}{\partial x}(3sin(\frac{6x)/y)) is (18cos((6x)/y))/(y)

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(\partial}{\partial x}(3sin(\frac{6x)/y))

\frac{\partial}{\partial x} (3 sin (\frac{6 x}{y}))

\frac{18 cos ( \frac{6 x}{y} )}{y}

Solution steps

\frac{\partial}{\partial x} (3 sin (\frac{6 x}{y}))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{\partial}{\partial x} (sin (\frac{6 x}{y}))

Apply the chain rule:

cos (\frac{6 x}{y}) \frac{\partial}{\partial x} (\frac{6 x}{y})

= cos (\frac{6 x}{y}) \frac{\partial}{\partial x} (\frac{6 x}{y})

\frac{\partial}{\partial x} (\frac{6 x}{y}) = \frac{6}{y}

= 3 cos (\frac{6 x}{y}) \frac{6}{y}

Simplify

3 cos (\frac{6 x}{y}) \frac{6}{y} : \frac{18 cos ( \frac{6 x}{y} )}{y}

= \frac{18 cos ( \frac{6 x}{y} )}{y}

x \to - \infty lim (\frac{5 + 2 x}{9 + 4 x ^{2}})

\int \frac{x + 3}{4 - x ^{2}} d x

2 x + 1, at x = \frac{1}{4}

n = 1 \sum \infty e^{- n} n!

f (x) = 8^{x}

What is (\partial}{\partial x}(3sin(\frac{6x)/y)) ?
The answer to (\partial}{\partial x}(3sin(\frac{6x)/y)) is (18cos((6x)/y))/(y)