What is the derivative of f(t)=1.3e^{0.7t} ?

The derivative of f(t)=1.3e^{0.7t} is 0.91e^{0.7t}

What is the first derivative of f(t)=1.3e^{0.7t} ?

The first derivative of f(t)=1.3e^{0.7t} is 0.91e^{0.7t}

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derivative of

f (t) = 1.3 e^{0.7 t}

0.91 e^{0.7 t}

Solution steps

\frac{d}{d t} (1.3 e^{0.7 t})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 1.3 \frac{d}{d t} (e^{0.7 t})

Apply the chain rule:

e^{0.7 t} \frac{d}{d t} (0.7 t)

= e^{0.7 t} \frac{d}{d t} (0.7 t)

\frac{d}{d t} (0.7 t) = 0.7

= 1.3 e^{0.7 t} \cdot 0.7

Simplify

= 0.91 e^{0.7 t}

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\frac{d}{d x} (ln (\frac{e ^{x}}{1 + e ^{x}}))

\frac{\partial}{\partial x} (ln ((cos (x) y)^{z}))

What is the derivative of f(t)=1.3e^{0.7t} ?
The derivative of f(t)=1.3e^{0.7t} is 0.91e^{0.7t}
What is the first derivative of f(t)=1.3e^{0.7t} ?
The first derivative of f(t)=1.3e^{0.7t} is 0.91e^{0.7t}