What is (\partial)/(\partial y)(sqrt(14-x^2-4y^2)) ?

The answer to (\partial)/(\partial y)(sqrt(14-x^2-4y^2)) is -(4y)/(sqrt(14-x^2-4y^2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(sqrt(14-x^2-4y^2))

\frac{\partial}{\partial y} (14 - x^{2} - 4 y^{2})

- \frac{4 y}{14 - x ^{2} - 4 y ^{2}}

Solution steps

\frac{\partial}{\partial y} (14 - x^{2} - 4 y^{2})

Treat

x

as a constant

Apply the chain rule:

\frac{1}{2 14 - x ^{2} - 4 y ^{2}} \frac{\partial}{\partial y} (14 - x^{2} - 4 y^{2})

= \frac{1}{2 14 - x ^{2} - 4 y ^{2}} \frac{\partial}{\partial y} (14 - x^{2} - 4 y^{2})

\frac{\partial}{\partial y} (14 - x^{2} - 4 y^{2}) = - 8 y

= \frac{1}{2 14 - x ^{2} - 4 y ^{2}} (- 8 y)

Simplify

\frac{1}{2 14 - x ^{2} - 4 y ^{2}} (- 8 y) : - \frac{4 y}{14 - x ^{2} - 4 y ^{2}}

= - \frac{4 y}{14 - x ^{2} - 4 y ^{2}}

x \to 2 lim (\frac{x ^{2} + 1}{x})

\frac{d}{d x} (e^{4} + ln (8))

\int e^{3 x + 4} d x

x \to 2 - lim (- 2)

y = x + 3, y = \frac{1}{2} x + 3

What is (\partial)/(\partial y)(sqrt(14-x^2-4y^2)) ?
The answer to (\partial)/(\partial y)(sqrt(14-x^2-4y^2)) is -(4y)/(sqrt(14-x^2-4y^2))