What is the derivative of sec(2x+tan(2x)) ?

The derivative of sec(2x+tan(2x)) is sec(2x)tan(2x)*2+sec^2(2x)*2

What is the first derivative of sec(2x+tan(2x)) ?

The first derivative of sec(2x+tan(2x)) is sec(2x)tan(2x)*2+sec^2(2x)*2

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\frac{d}{d x} (sec (2 x) + tan (2 x))

sec (2 x) tan (2 x) \cdot 2 + sec^{2} (2 x) \cdot 2

Solution steps

\frac{d}{d x} (sec (2 x) + tan (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sec (2 x)) + \frac{d}{d x} (tan (2 x))

\frac{d}{d x} (sec (2 x)) = sec (2 x) tan (2 x) \cdot 2

\frac{d}{d x} (tan (2 x)) = sec^{2} (2 x) \cdot 2

= sec (2 x) tan (2 x) \cdot 2 + sec^{2} (2 x) \cdot 2

x^{2} - 4 x y + y^{2} = 4

\int (3 x - 1)^{2} d x

\int cos (8 x) d x

f (x) = e^{x} x

\int \frac{x ^{2} - 36}{x ^{3}} d x

What is the derivative of sec(2x+tan(2x)) ?
The derivative of sec(2x+tan(2x)) is sec(2x)tan(2x)*2+sec^2(2x)*2
What is the first derivative of sec(2x+tan(2x)) ?
The first derivative of sec(2x+tan(2x)) is sec(2x)tan(2x)*2+sec^2(2x)*2