What is (\partial)/(\partial y)(x^2ycos(z/t)) ?

The answer to (\partial)/(\partial y)(x^2ycos(z/t)) is x^2cos(z/t)

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(\partial)/(\partial y)(x^2ycos(z/t))

\frac{\partial}{\partial y} (x^{2} y cos (\frac{z}{t}))

x^{2} cos (\frac{z}{t})

Solution steps

\frac{\partial}{\partial y} (x^{2} y cos (\frac{z}{t}))

Treat

x, z, t

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} cos (\frac{z}{t}) \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= x^{2} cos (\frac{z}{t}) \cdot 1

Simplify

= x^{2} cos (\frac{z}{t})

y^{^{'}} - \frac{8}{x} y = (\frac{y}{x ^{6}})^{3}

- 5 x

y^{^{''}} + 6 y^{^{'}} + 13 y = 0

\int \frac{x ^{3}}{64} d x

\int (x^{2} - x + 3) d x

What is (\partial)/(\partial y)(x^2ycos(z/t)) ?
The answer to (\partial)/(\partial y)(x^2ycos(z/t)) is x^2cos(z/t)