What is the tangent of x^2+y^2=169,(-12,5) ?

The tangent of x^2+y^2=169,(-12,5) is y= 12/5 x+169/5

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tangent of x^2+y^2=169,(-12,5)

tangent of

x^{2} + y^{2} = 169, (- 12, 5)

y = \frac{12}{5} x + \frac{169}{5}

Solution steps

Find the slope of

x^{2} + y^{2} = 169 : \frac{d y}{d x} = - \frac{x}{y}

Compute the slope of

x^{2} + y^{2} = 169

(- 12, 5) : m = \frac{12}{5}

Find the line with slope m=

\frac{12}{5}

and passing through

(- 12, 5) : y = \frac{12}{5} x + \frac{169}{5}

y = \frac{12}{5} x + \frac{169}{5}

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1 + 10 t

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What is the tangent of x^2+y^2=169,(-12,5) ?
The tangent of x^2+y^2=169,(-12,5) is y= 12/5 x+169/5