What is the sum from n=6 to infinity of (7^n)/(12^n) ?

The sum from n=6 to infinity of (7^n)/(12^n) is converges

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sum from n=6 to infinity of (7^n)/(12^n)

n = 6 \sum \infty \frac{7 ^{n}}{1 2 ^{n}}

converges

Solution steps

n = 6 \sum \infty \frac{7 ^{n}}{1 2 ^{n}}

n \to \infty lim (n (\frac{\frac{7 ^{n}}{1 2 ^{n}}}{\frac{7 ^{n + 1}}{1 2 ^{n + 1}}} - 1)) = \infty

L > 1,

by the Raabe's test

= converges

\int 6 cos (5 x) d x

\int_{0}^{3} 4 π (\frac{x ^{3}}{3}) d x

1 + 10 t

\int 10 - x d x

f (x) = \frac{x ^{3}}{4}, (- 6, - 54)

What is the sum from n=6 to infinity of (7^n)/(12^n) ?
The sum from n=6 to infinity of (7^n)/(12^n) is converges