What is the tangent of f(x)=(x^3)/4 ,(-6,-54) ?

The tangent of f(x)=(x^3)/4 ,(-6,-54) is y=27x+108

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tangent of f(x)=(x^3)/4 ,(-6,-54)

tangent of

f (x) = \frac{x ^{3}}{4}, (- 6, - 54)

y = 27 x + 108

Solution steps

Find the slope of

f (x) = \frac{x ^{3}}{4} : \frac{df ( x )}{d x} = \frac{3 x ^{2}}{4}

Compute the slope of

f (x) = \frac{x ^{3}}{4}

(- 6, - 54) : m = 27

Find the line with slope m=

27

and passing through

(- 6, - 54) : y = 27 x + 108

y = 27 x + 108

\frac{\partial}{\partial x} (sin (3 x) cos (2 y))

\int (sin (x))^{\frac{1}{3}} cos (x) d x

\int_{6}^{13} ln (x - 6) d x

x \to 0 lim (25)

What is the tangent of f(x)=(x^3)/4 ,(-6,-54) ?
The tangent of f(x)=(x^3)/4 ,(-6,-54) is y=27x+108