What is the solution for x^2y^'+2xy=e^{3x} ?

The solution for x^2y^'+2xy=e^{3x} is y=(e^{3x})/(3x^2)+(c_{1})/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2y^'+2xy=e^{3x}

x^{2} y^{^{'}} + 2 x y = e^{3 x}

y = \frac{e ^{3 x}}{3 x ^{2}} + \frac{c _{1}}{x ^{2}}

Solution steps

x^{2} y^{'} (x) + 2 x y = e^{3 x}

Solve linear ODE:

y = \frac{e ^{3 x}}{3 x ^{2}} + \frac{c _{1}}{x ^{2}}

y = \frac{e ^{3 x}}{3 x ^{2}} + \frac{c _{1}}{x ^{2}}

\int_{1}^{3} \frac{x ^{2} + 4}{x} d x

\int 20 x^{19} d x

\int_{0}^{1} x a x^{2} + b d x

sin^{2} (θ)

y^{^{'}} = \frac{6 t ^{2}}{y}

What is the solution for x^2y^'+2xy=e^{3x} ?
The solution for x^2y^'+2xy=e^{3x} is y=(e^{3x})/(3x^2)+(c_{1})/(x^2)