What is the solution for y^'=(6t^2)/y ?

The solution for y^'=(6t^2)/y is y=sqrt(4t^3+c_{1)},y=-sqrt(4t^3+c_{1)}

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y^'=(6t^2)/y

y^{^{'}} = \frac{6 t ^{2}}{y}

y = 4 t^{3} + c_{1}, y = - 4 t^{3} + c_{1}

Solution steps

y^{'} (t) = \frac{6 t ^{2}}{y}

Solve separable ODE:

y = 4 t^{3} + c_{1}, y = - 4 t^{3} + c_{1}

y = 4 t^{3} + c_{1}, y = - 4 t^{3} + c_{1}

\int_{- 1}^{1} x^{2} 5 - 3 x d x

\frac{3}{s ^{2} + 2 s + 5}

\frac{d}{d x} (2 x^{4} + 3 x - 3)

\int_{- \infty}^{- 1} e^{- 6 t} d t

4 sin (x), 4 cos (2 x), - \frac{π}{2}, \frac{π}{6}

What is the solution for y^'=(6t^2)/y ?
The solution for y^'=(6t^2)/y is y=sqrt(4t^3+c_{1)},y=-sqrt(4t^3+c_{1)}