What is the integral from-infinity to-1 of e^{-6t} ?

The integral from-infinity to-1 of e^{-6t} is diverges

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integral from-infinity to-1 of e^{-6t}

\int_{- \infty}^{- 1} e^{- 6 t} d t

diverges

Solution steps

\int_{- \infty}^{- 1} e^{- 6 t} d t

Compute the indefinite integral:

\int e^{- 6 t} d t = - \frac{1}{6} e^{- 6 t} + C

Compute the boundaries:

\int_{- \infty}^{- 1} e^{- 6 t} d t =

diverges

= diverges

4 sin (x), 4 cos (2 x), - \frac{π}{2}, \frac{π}{6}

\frac{d}{d x} ((x - 1) (x + 1)^{2})

x \to 0 lim (x^{l n (x)})

e^{8 x}

x \to 0 lim (\frac{cot ( 7 x )}{csc ( 7 x )})

What is the integral from-infinity to-1 of e^{-6t} ?
The integral from-infinity to-1 of e^{-6t} is diverges