What is the integral of 1/(5+sqrt(2x)) ?

The integral of 1/(5+sqrt(2x)) is 5+sqrt(2)sqrt(x)-5ln|5+sqrt(2)sqrt(x)|+C

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integral of 1/(5+sqrt(2x))

\int \frac{1}{5 + 2 x} d x

5 + 2 x - 5 ln 5 + 2 x + C

Solution steps

\int \frac{1}{5 + 2 x} d x

Apply u-substitution

: \int \frac{u - 5}{u} d u

= \int \frac{u - 5}{u} d u

Expand

\frac{u - 5}{u} : 1 - \frac{5}{u}

= \int 1 - \frac{5}{u} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d u - \int \frac{5}{u} d u

\int 1 d u = u

\int \frac{5}{u} d u = 5 ln ∣ u ∣

= u - 5 ln ∣ u ∣

Substitute back

u = 5 + 2 x

= 5 + 2 x - 5 ln 5 + 2 x

Simplify

5 + 2 x - 5 ln 5 + 2 x : 5 + 2 x - 5 ln 5 + 2 x

= 5 + 2 x - 5 ln 5 + 2 x

Add a constant to the solution

= 5 + 2 x - 5 ln 5 + 2 x + C

\int x - 9 cos (x) d x

y = \frac{5}{x}, y = \frac{5}{x ^{2}}, x = 6

x \to 0 lim (x^{x^{x}})

(x^{2} + 1) \frac{d y}{d x} + x y - x = 0

\frac{d}{d x} (2^{7 x})

What is the integral of 1/(5+sqrt(2x)) ?
The integral of 1/(5+sqrt(2x)) is 5+sqrt(2)sqrt(x)-5ln|5+sqrt(2)sqrt(x)|+C