What is the derivative of x^3-4/x ?

The derivative of x^3-4/x is 3x^2+4/(x^2)

What is the first derivative of x^3-4/x ?

The first derivative of x^3-4/x is 3x^2+4/(x^2)

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\frac{d}{d x} (x^{3} - \frac{4}{x})

3 x^{2} + \frac{4}{x ^{2}}

Solution steps

\frac{d}{d x} (x^{3} - \frac{4}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (\frac{4}{x})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= 3 x^{2} - (- \frac{4}{x ^{2}})

Simplify

= 3 x^{2} + \frac{4}{x ^{2}}

y = \frac{2 x}{( x + 1 ) ^{2}}, (0, 0)

y^{^{'}} + (cot (x)) y = sin^{2} (x)

\frac{ln ( x )}{5 x ^{2}}

\frac{\partial}{\partial x} (e^{2 x + 7 y})

y^{^{''}} + 6 y^{^{'}} + 9 y = 6 t^{2} e^{- 3 t}

What is the derivative of x^3-4/x ?
The derivative of x^3-4/x is 3x^2+4/(x^2)
What is the first derivative of x^3-4/x ?
The first derivative of x^3-4/x is 3x^2+4/(x^2)