What is the limit as x approaches 0 of 8/(x^2+x)-8/x ?

The limit as x approaches 0 of 8/(x^2+x)-8/x is -8

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limit as x approaches 0 of 8/(x^2+x)-8/x

x \to 0 lim (\frac{8}{x ^{2} + x} - \frac{8}{x})

- 8

Solution steps

x \to 0 lim (\frac{8}{x ^{2} + x} - \frac{8}{x})

Simplify

\frac{8}{x ^{2} + x} - \frac{8}{x} : - \frac{8}{x + 1}

= x \to 0 lim (- \frac{8}{x + 1})

Plug in the value

x = 0

= - \frac{8}{0 + 1}

Simplify

= - 8

x \to 1 lim (\frac{1}{a x + 2})

\int_{- 5}^{1} ∣ x + 2 ∣ d x

\frac{\partial}{\partial y} (- 4 y)

ln (\frac{x ^{2} + 1}{x + 1})

What is the limit as x approaches 0 of 8/(x^2+x)-8/x ?
The limit as x approaches 0 of 8/(x^2+x)-8/x is -8