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Popular >

integral from-5 to 1 of |x+2|

Solution

\int_{- 5}^{1} ∣ x + 2 ∣ d x

Solution

9

Solution steps

\int_{- 5}^{1} ∣ x + 2 ∣ d x

Eliminate Absolutes

= \int_{- 5}^{- 2} - x - 2 d x + \int_{- 2}^{1} x + 2 d x

\int_{- 5}^{- 2} - x - 2 d x = \frac{9}{2}

\int_{- 2}^{1} x + 2 d x = \frac{9}{2}

= \frac{9}{2} + \frac{9}{2}

Simplify

\frac{9}{2} + \frac{9}{2} : 9

= 9

Popular Examples

(\partial)/(\partial y)(-4y)

\frac{\partial}{\partial y} (- 4 y)

derivative of ln((x^2+1)/(x+1))derivative of

ln (\frac{x ^{2} + 1}{x + 1})

integral of sqrt(1+2x^4)(8x^3)

\int 1 + 2 x^{4} (8 x^{3}) d x

y^{^{'}} = \frac{x}{y}

derivative of x^3+2x^2

\frac{d}{d x} (x^{3} + 2 x^{2})

Frequently Asked Questions (FAQ)

What is the integral from-5 to 1 of |x+2| ?
The integral from-5 to 1 of |x+2| is 9