en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'= x/y

Solution

y^{^{'}} = \frac{x}{y}

Solution

y = x^{2} + c_{1}, y = - x^{2} + c_{1}

Solution steps

y^{'} (x) = \frac{x}{y}

Solve separable ODE:

y = x^{2} + c_{1}, y = - x^{2} + c_{1}

y = x^{2} + c_{1}, y = - x^{2} + c_{1}

Popular Examples

derivative of x^3+2x^2

\frac{d}{d x} (x^{3} + 2 x^{2})

(\partial)/(\partial x)(xln(z^4+x^7))

\frac{\partial}{\partial x} (x ln (z^{4} + x^{7}))

tangent of f(x)=(2x)/(x^2+1),\at x=-1 tangent of

f (x) = \frac{2 x}{x ^{2} + 1}, at x = - 1

integral of e^{4t}

\int e^{4 t} d t

((x-sqrt(x))*(x+sqrt(x)))^'

((x - x) \cdot (x + x))^{^{'}}

Frequently Asked Questions (FAQ)

What is the solution for y^'= x/y ?
The solution for y^'= x/y is y=sqrt(x^2+c_{1)},y=-sqrt(x^2+c_{1)}