What is the derivative of x^3+2x^2 ?

The derivative of x^3+2x^2 is 3x^2+4x

What is the first derivative of x^3+2x^2 ?

The first derivative of x^3+2x^2 is 3x^2+4x

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\frac{d}{d x} (x^{3} + 2 x^{2})

3 x^{2} + 4 x

Solution steps

\frac{d}{d x} (x^{3} + 2 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

= 3 x^{2} + 4 x

\frac{\partial}{\partial x} (x ln (z^{4} + x^{7}))

f (x) = \frac{2 x}{x ^{2} + 1}, at x = - 1

\int e^{4 t} d t

((x - x) \cdot (x + x))^{^{'}}

\frac{d}{d x} (3 sin (2 x) + e^{- x})

What is the derivative of x^3+2x^2 ?
The derivative of x^3+2x^2 is 3x^2+4x
What is the first derivative of x^3+2x^2 ?
The first derivative of x^3+2x^2 is 3x^2+4x