What is the integral of (3sin(x)-2cos(x)) ?

The integral of (3sin(x)-2cos(x)) is -3cos(x)-2sin(x)+C

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integral of (3sin(x)-2cos(x))

\int (3 sin (x) - 2 cos (x)) d x

- 3 cos (x) - 2 sin (x) + C

Solution steps

\int 3 sin (x) - 2 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 sin (x) d x - \int 2 cos (x) d x

\int 3 sin (x) d x = - 3 cos (x)

\int 2 cos (x) d x = 2 sin (x)

= - 3 cos (x) - 2 sin (x)

Add a constant to the solution

= - 3 cos (x) - 2 sin (x) + C

n = 2 \sum \infty \frac{1}{2 ^{n - 1}}

45 x^{8} - 12 x^{5}

\frac{d}{d x} (\frac{96}{x})

11 x - 4 y x^{2} + 1 y^{^{'}} = 0

f (x) = 11 x

What is the integral of (3sin(x)-2cos(x)) ?
The integral of (3sin(x)-2cos(x)) is -3cos(x)-2sin(x)+C