What is the derivative of (16x/((4-x^2)^2)) ?

The derivative of (16x/((4-x^2)^2)) is (16(3x^2+4))/((4-x^2)^3)

What is the first derivative of (16x/((4-x^2)^2)) ?

The first derivative of (16x/((4-x^2)^2)) is (16(3x^2+4))/((4-x^2)^3)

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\frac{d}{d x} (\frac{16 x}{( 4 - x ^{2} ) ^{2}})

\frac{16 ( 3 x ^{2} + 4 )}{( 4 - x ^{2} ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{16 x}{( 4 - x ^{2} ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d x} (\frac{x}{( 4 - x ^{2} ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 16 \cdot \frac{\frac{d x}{d x} ( 4 - x ^{2} ) ^{2} - \frac{d}{d x} ( ( 4 - x ^{2} ) ^{2} ) x}{( ( 4 - x ^{2} ) ^{2} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} ((4 - x^{2})^{2}) = - 4 x (4 - x^{2})

= 16 \cdot \frac{1 \cdot ( 4 - x ^{2} ) ^{2} - ( - 4 x ( 4 - x ^{2} ) ) x}{( ( 4 - x ^{2} ) ^{2} ) ^{2}}

Simplify

16 \cdot \frac{1 \cdot ( 4 - x ^{2} ) ^{2} - ( - 4 x ( 4 - x ^{2} ) ) x}{( ( 4 - x ^{2} ) ^{2} ) ^{2}} : \frac{16 ( 3 x ^{2} + 4 )}{( 4 - x ^{2} ) ^{3}}

= \frac{16 ( 3 x ^{2} + 4 )}{( 4 - x ^{2} ) ^{3}}

\int \frac{1}{2 x ^{2} + 3 x + 1} d x

\frac{\partial}{\partial x} (4 sin (6 x - 7 y))

\int - 2 t^{5} d t

(x^{2} - 9)^{2}

\int (x^{2} + \frac{1}{( 3 x ) ^{2}}) d x

What is the derivative of (16x/((4-x^2)^2)) ?
The derivative of (16x/((4-x^2)^2)) is (16(3x^2+4))/((4-x^2)^3)
What is the first derivative of (16x/((4-x^2)^2)) ?
The first derivative of (16x/((4-x^2)^2)) is (16(3x^2+4))/((4-x^2)^3)